A 1.5 kg box is initially at rest on a horizontal surface when at t = 0 a horizontal force 
(with t in seconds) is applied to the box. The acceleration of the box as a function of time t is given by: (g = 10m/s 2 )
for 0 
t 
2.85
m/s 2 for t > 2.85
The coefficient of kinetic friction between the box and the surface is:
Text Solution
Verified by ExpertsThe correct answer is:
B
1.8 t – µ k 15 = 1.5 (1.2 t – 2.4)
for t = 2.85 sec.
µ k = 0.24
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